In borax bead test of ${C o}^{2 +}$ the blue colour of bead is due to :

C o_{3} B_{2}

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C o {(B O 2)}_{2}

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C o O

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none of the above

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Solution

The correct option is D $C o {(B O 2)}_{2}$
In borax bead test, the colour given by $C o^{2 +}$ is blue.
$N a_{2} B_{4} O_{7} .10 H_{2} O - \to △ 2 N a B O_{2} + B_{2} O_{3} + 10 H_{2} O$

$B_{2} O_{3} + C o O ⟶ C o (B O_{2})_{2} (B l u e)$

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