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Potassium Dichromate

In both cryst...

Question

In both crystalline NaHCO3 and KHCO3,HCO3- forms only dimeric anion through hydrogen bond.justify this statement.

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Solution

The bicarbonates of sodium and potassium (NaHCO3 and KHCO3) have ionic, covalent and hydrogen bonds in pure state.

In KHCO3, there is ionic bonding beween K+ and HCO3- ions, and the bonding within the bicarbonate ion (HCO3-) is covalent. And, the HCO3- ions exist as dimers by means of hydrogen bonding.

In NaHCO3, the HCO3- ions are linked in an infinite fashion by hydrogen bonding.

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Q. Which of the following statements are correct?
(I) Both melting and boiling points of

H_{2} O

are higher than those of

H_{2} T e

N_{2} O_{5}

N_{2} O_{4}

N - O

bond lengths are equivalent.
(III) In both crystalline

N a H C O_{3}

K H C O_{3} . H C O_{3}^{-}

forms only dimeric anion through hydrogen bond.
(IV)

B_{2}, C_{2}, N_{2}

on further ionization (removal of single electron) form thermodynamically less stable species.

Q. Which of the following statements are correct?
(I) Both melting and boiling points of

H_{2} O

are higher than those of

H_{2} T e

N_{2} O_{5}

N_{2} O_{4}

N - O

bond lengths are equivalent.
(III) In both crystalline

N a H C O_{3}

K H C O_{3} . H C O_{3}^{-}

forms only dimeric anion through hydrogen bond.
(IV)

B_{2}, C_{2}, N_{2}

on further ionization (removal of single electron) form thermodynamically less stable species.

in solid KHCO3,HCO3–(anion) ions exist as

Monomer

Dimer

Polymer

H+ & CO3(2-)

{H C O_{3}}^{-}

ions joined by H-bonding in

K H C O_{3}

Q. In a solution of

N a H C O_{3}

, the amphiprotic anion undergoes ionization to form

H^{+}

ion and hydrolysis to form

O H^{-} i o n

H C O_{3}^{-} + H_{2} O i o n i z a t i o n ⇋ C O_{3}^{2 -} + H_{2} O

H C O_{3}^{-} + H_{2} O i o n i z a t i o n ⇋ H_{2} C O_{3} + O H^{-}

To calculate pH of the above solutions, the suitable approximation is

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