In BrF3 molecule, the lone pairs occupy equatorial position to minimize :
A
lone pair - bond pair repulsion only
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B
bond pair - bond pair repulsion only
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C
lone pair - lone pair repulsion and lone pair - bond pair repulsion
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D
lone pair - lone pair repulsion only
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Solution
The correct option is A lone pair - lone pair repulsion only
Lone pair repulsion is greater than bond pair repulsion. Therefore, to attain stability, the lone pairs should be kept at a position farthest from each other, so they occupy the equatorial positions.