In brown ring test, which compound is responsible for ring formation?

$F e S O_{4} . N O_{2}$

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$F e S O_{4} . N O$

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$F e S O_{4} . N_{2} O$

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None of the above

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Solution

The correct option is B
$F e S O_{4} . N O$

As Ferrous sulphate reacts with Nitrogen oxide, a compound called Nitroso ferrous sulphate is formed which is responsible for brown ring formation.

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Similar questions

The chemical formula of brown ring formed in the brown ring test is .

{N O}_{3}^{-}

{[F e {(H_{2} O)}_{5} N O]}^{2 +}

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