In C.G.S. system, the magnitude of a force is 100 dynes. In another system where the fundamental physical quantities are kilogram, metre and minute, the magnitude of the force is
A
0.036
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B
0.36
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C
3.6
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D
36
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Solution
The correct option is C 3.6 We know that the dimension of Force is MLT−2, Let the magnitude of force in the new system be n2 n2=100(M1M2)1(L1L2)1(T1T2)−2 =100(gmkg)1(cmm)1(secmin)−2 =100(gm103gm)1(cm102cm)1(sec60sec)−2 n2=100×3600105=3.6