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Question

In C.G.S system the magnitude of the force is $$100$$ dyne. In another system where the fundamental physical quantities are kilogram, metre, and minute, the magnitude of force is:


A
0.036
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B
0.36
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C
3.6
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D
36
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Solution

The correct option is C $$3.6$$

$$Force=M^{1}L^{1}T^{-2}=100\dfrac{gm cm}{s^{2}}$$

                                    $$\displaystyle =100\times
\frac{(10^{-3})kg\ \times (10^{-2})m}{(\frac{1}{60})^{2}\ (min)^{2}}$$

                                    $$\displaystyle =3.6\frac{kg\ m}{(min)^{2}}$$


Physics

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