In $C + H_{2} O \to C O + H_{2}$
$H_{2} O$ acts as

Oxidising agent

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Reducing agent

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(a) & (b) both

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None of these

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Solution

The correct option is A Oxidising agent
In the reaction $H_{2} O$ acts as oxidizing agent since the oxidation number of hydrogen reduces from +1 to 0

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Similar questions

C + H_{2} O \to C O + H_{2}

H_{2} O

C + H_{2} O ⟶ C O + H_{2}, H_{2} O

In $C + H_{2} O ⟶ C O + H_{2}, H_{2} O$ acts as a:

H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}

H_{2} O_{2}

C + H_{2} O ⟶ C O + H_{2}, H_{2} O

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