In Cannizzaro reaction given below-Ph - CHO OH - P h - CH 2- OH - P hCOO -The slowest step is-A- The attack of OH -at the carbonyl groupB- The transfer of hydride to the carbonyl groupC- The abstraction of proton from carboxylic acidD- The protonation of P h - COOH

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Synthetic Dyes

In Cannizzaro...

Question

In Cannizzaro reaction given below:
$P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}$
The slowest step is:

The attack of

O H^{-}

at the carbonyl group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The transfer of hydride to the carbonyl group

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The abstraction of proton from carboxylic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The protonation of

P h - C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

Join BYJU'S Learning Program