In Cannizzaro reaction given below-Ph - CHO OH - P h - CH 2- OH - P hCOO -The slowest step is-A- The attack of OH -at the carbonyl groupB- The transfer of hydride to the carbonyl groupC- The abstraction of proton from carboxylic acidD- The protonation of P h - COOH

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In Cannizzaro...

Question

In Cannizzaro reaction given below:
$P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}$
The slowest step is:

The attack of

O H^{-}

at the carbonyl group

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The transfer of hydride to the carbonyl group

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The abstraction of proton from carboxylic acid

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The protonation of

P h - C O O H

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Solution

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Similar questions

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

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