Question

In carbon disulphide $\left(C{S}_4\right)$, the mass of sulphur in combination with $3.0g$ of carbon is

• A. $4.0g$
• B. $6.0g$
• C. $64.0g$
• D. $16.0g$

Answer 1

The correct option is D $16.0g$

Given, Carbon disulphide $C{S}_2$

Molar mass of $C{S}_2=12g+32\times 2g$

$=12+64g=76g$

i.e; $12g$ of $C$ reacts with $64g$ of $S$ to form $76g$ $C{S}_2$

Also, in $12g$ of $C$ forms $76g$ $C{S}_2$

$\Rightarrow 3.0g$ of $C$ forms $\frac{76\times 3}{12}g$ of $C{S}_2$

$\Rightarrow 19g$ of $C{S}_2$ is formed.

Also,

If $76g$ $C{S}_2$ has $64g$ of $S$

then, $19g$ $C{S}_2$ will have $\frac{19\times 64}{76}g$ of $S$

$\Rightarrow 16.0g$ of $S$ is present.