In Carius method, of estimation of halogens, $250 m g$ of an organic compound gave $141 m g$ of $A g B r$ . The percentage of bromine in the compound is:
[Atomic mass $A g = 108, B r = 80$ amu]

24

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

36

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $24$
Hence, the correct option is $A$

Suggest Corrections

Similar questions

Q. In Carius method of estimation of halogens, 250

m g

of an organic compound gave 141

m g

A g B r

. The percentage of bromine in the compound is:
(Atomic mass of

A g

= 108, Br= 80)

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is (At. Mass Ag = 108; Br = 80)

Q. In the Carius method for the estimation of halogen, 0.18 g of an monobromo organic compound gave 0.12 g of

A g B r

. The percentage of bromine in the compound is:
(Atomic mass of Br = 80 u, Ag = 108 u)

Q. In carius method of estimation of halogens, 250 mg of an oraganic compound gave 141 mg of AgBr. The percentage of bromine in the compound is ( at mass: Ag= 108, Br=80)

Q. In Carius method of estimation of halogen 0.15 gram of an organic compound gave 0.12 gram of AgBr . calculate % of bromine in the compound. (Ag=108, Br=80)

Join BYJU'S Learning Program

In Carius method, of estimation of halogens, 250mg of an organic compound gave 141mg of AgBr. The percentage of bromine in the compound is:[Atomic mass Ag=108,Br=80 amu]

The correct option is A 24Hence, the correct option is A

In Carius method, of estimation of halogens, $250 m g$ of an organic compound gave $141 m g$ of $A g B r$ . The percentage of bromine in the compound is:
[Atomic mass $A g = 108, B r = 80$ amu]

The correct option is A $24$
Hence, the correct option is $A$