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Introduction of VSEPR

In case of ni...

Question

In case of nitrogen, $N C l_{3}$ is possible but not $N C l_{5},$ while in case of phosphorous. $P C l_{3}$ as well as $P C l_{5}$ are possible. It is due to

lower electronegativity of P but not in N

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lower tendency of H bond formation in P than N

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availability of vacant d-orbital in P but not in N

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occurrence of P in solid while N in gaseous state at room temperature.

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Solution

The correct option is D availability of vacant d-orbital in P but not in N
In case of nitrogen, $N C l_{3}$ is possible but not $N C l_{5}$ , while in case of phosphorous $P C l_{3}$ as well as $P C l_{5}$ both are possible due to in Nitrogen vacant d-orbitals are not available, but in case of Phosphorous vacant 3d-orbitals are available.

So, the correct option is C.

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Similar questions

Q. In case of nitrogen,

N C l_{3}

is possible but not

N C l_{5}

, whereas in case of phosphorous,

P C l_{3}

as well as

P C l_{5}

are possible. It is due to:

Q. In case of nitrogen,

N C l_{3}

is possible but not

N C l_{5}

while in case of phosphorus,

P C l_{3}

as well as

P C l_{5}

are possible. It is due to:

Q. The hybrid states of phosphorous atoms in

P C l_{5}

and

P B r_{3}

in gaseous phase are

s p^{3} d

. But in solid

P C l_{5}

, phosphorous shows

s p^{3} d^{2}

hybrid state. While

P

P B r

is in

s p^{3}

hybrid state. This is because :

Q. Assertion :

P C l_{4}

exists but

N C l_{5}

does not exist. Reason:

d -

orbital in

P -

atom takes part in chemical bonding, this lacks in

N -

atom.

Q. Assertion: Both rhombic and monoclinic sulphur exist as

S_{8}

but oxygen exists as

O_{2} .

Reason: Oxygen form

p π - p π

multiple bond due to small size and small bond length but

p π - p π

bonding is not possible in sulphur due to its larger atomic size than oxygen.

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In case of nitrogen, NCl3 is possible but not NCl5, while in case of phosphorous. PCl3 as well as PCl5 are possible. It is due to

In case of nitrogen, $N C l_{3}$ is possible but not $N C l_{5},$ while in case of phosphorous. $P C l_{3}$ as well as $P C l_{5}$ are possible. It is due to