Question

In case of polyembryony, if an embryo develops from the synergid and another from the nucellus, then the synergid embryo is $\underset{–}{\left(i\right)}$ and nuclear embryo is $\underset{–}{\left(ii\right)}$.

• A. (i)- triploid, (ii)-haploid
• B. (i)-diploid, (ii)-haploid
• C. (i)-haploid, (ii)-diploid
• D. (i)-diploid, (ii)-triploid

Answer 1

The correct option is C (i)-haploid, (ii)-diploid

So The presence of more than one embryo in a seed is called polyembryony, e.g. lemon, groundnut, etc. Polyembryony plays the main role in plant breeding and horticulture. The plantlets obtained from these embryos are virus-free and have more vigor. Embryo developed from the synergid is haploid as the ploidy of the synergid is haploid.
Embryo developed from the nucellus is diploid as the ploidy of the nucellus is diploid.

So the correct answer should be option C "(i)-haploid (ii)- diploid"