In case where battery is removed and dielectric is inserted Electric field of dielectric changes and not the Electric field of plates. What does this mean?

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Q. A parallel plate capacitors of capacitance

C_{0}

is charged to voltage

V

and then battery is disconnected. A dielectric covering one third area of each plate is now inserted. Charges on plates get redistributed such that portion covered by dielectric and vaccum shares equal amount of charge, then which of the statements are true?

Q. A parallel plate capacitor is charged by a battery and the battery remains connected, a dielectric slab is inserted in the space between the plates. Explain what changes if any, occur in the values of the
(i) potential difference between the plates
(ii) electric field between the plates
(ii) energy stored in the capacitor

When a dielectric material is introduced between the plates of a charged condenser, after disconnecting the battery, the electric field between the plates:

(1): The strength of the electric field in the charged and isolated capacitor is decreased when the dielectric slab is inserted.

(2): When the dielectric slab is inserted between the plates of a charged capacitor, the electric field produced due to induced charge, opposite to the external field.

Q. A capacitor of capacitance ‘C’ is connected with a battery of emf ε as shown. After full charging a dielectric of same size of capacitor and dielectric constant k is inserted then choose correct statements. (capacitor is always connected to battery)

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