wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In CBS, seg BC seg SC ray CE bisects DCS.
ray SE || ray BC. Prove that CBSE is a parallelogram (see fig. 5.6)

Open in App
Solution

We can see that DCS = CBS + CSB (Exterior angle property)
DCE + ECS = CBS + CSB
CES + ECS = CBS + CSB (CE bisects DCE)
2ECS = CSB + CSB (Angles opposite to equal sides are equal )
2ECS = 2CSB
ECS = CSB

Since, alternate angles are equal, CE and BS are parallel.
Since, each pair of opposite sides of a quadrilateral are parallel, CBSE is a parallelogram.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Parallelograms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon