In certain temprature compound AB2g dissociates according to the reaction 2AB2g- 2ABg-B2gWith degree of dissociation - which is small compared with unity- The expression of KP- in terms of - and initial pressure P is-

At certain temperature, a compound $A B_{2}$ dissociates as: $2 A B_{2 (g)} \to 2 A B_{(g)} + B_{2 (g)}$ with a degree of dissociation $α$ , which is very small compared to unity. The expression of $K_{p}$ in terms of $α$ and total pressure P is ?

Q. At temperature

T

, a compound

{A B}_{2} (g)

dissociates according to the reaction

2 {A B}_{2} (g) \Leftrightarrow 2 A B (g) + B_{2} (g)

with a degree of dissociation,

x

, which is small compared with unity. Deduce the expression for

K_{p}

in terms of

x

and the total pressure

P

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In certain temprature compound AB2(g) dissociates according to the reaction 2AB2g⇌2AB(g)+B2(g) With degree of dissociation α, which is small compared with unity. The expression of KP, in terms of α and initial pressure P is:

The correct option is A Pα322AB2(g)⇌2AB(g)+B2(g) P 0 0 P(1−α) Pα Pα2 Kp=(Pα)2.(Pα2)(P(1−α))2,1−α<<1 ∴Kp=Pα32

In certain temprature compound $A B_{2} (g)$ dissociates according to the reaction
$2 A B_{2} g ⇌ 2 A B (g) + B_{2} (g)$
With degree of dissociation $α$ , which is small compared with unity. The expression of $K_{P}$ , in terms of $α$ and initial pressure P is:

The correct option is A $P \frac{α^{3}}{2}$
$2 A B_{2} (g) ⇌ 2 A B (g) + B_{2} (g)$
$P 00$
$P (1 - α) P α \frac{P α}{2}$
$K p = \frac{(P α)^{2} . (\frac{P α}{2})}{(P (1 - α))^{2}}, 1 - α << 1$
$∴ K p = \frac{P α^{3}}{2}$