In chromite ore, the oxidation number of iron, and chromium are respectively.

+3, +2

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+3, +6

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+2, +6

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+2, +3

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Solution

The correct option is B +2, +3
Chromite or chrome iron ore is $F e C r_{2} O_{4}$ . Its actual composition is $F e O . C r_{2} O_{3}$ .

In $F e O$ , oxidation state of $F e$ is calculated as:

$x + (- 2) = 0$
$x = + 2$

Similarly, in $C r_{2} O_{3}$ , the oxidation state of $C r$ is calculated as

$2 \times x + (- 2) \times 3 = 0$
$2 x = + 6$
$x = + 3$

Hence, the correct option is $D$

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