In chromium chloride $(C r C l_{3})$ , $C l^{-}$ ions have cubic close packed arrangement and $C r^{3 +}$ ions are present in the octahedral holes. The fraction of the total number of holes occupied is:

1 / 3

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1 / 6

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1 / 9

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1 / 12

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Solution

The correct option is A $1 / 3$
In CCP, No. of Tetrahedral holes $= 8$
No. of Octahedral holes $= 4$
Total $= 12$ holes
$C r^{+ 3}$ ions are in octahedral holes
Fraction of occupied holes $= \frac{4}{12} = \frac{1}{3}$

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In chromium chloride (CrCl3), Cl− ions have cubic close packed arrangement and Cr3+ ions are present in the octahedral holes. The fraction of the total number of holes occupied is:

The correct option is A 1/3In CCP, No. of Tetrahedral holes =8No. of Octahedral holes =4Total =12 holesCr+3 ions are in octahedral holesFraction of occupied holes =412=13

In chromium chloride $(C r C l_{3})$ , $C l^{-}$ ions have cubic close packed arrangement and $C r^{3 +}$ ions are present in the octahedral holes. The fraction of the total number of holes occupied is:

The correct option is A $1 / 3$
In CCP, No. of Tetrahedral holes $= 8$
No. of Octahedral holes $= 4$
Total $= 12$ holes
$C r^{+ 3}$ ions are in octahedral holes
Fraction of occupied holes $= \frac{4}{12} = \frac{1}{3}$