In chromium (III) chloride, (CrCl3), chloride ions have cubic close packed arrangement and Cr(III) ions are present in octahedral voids.
Choose the correct option(s):
A
Fraction of octahedral voids occupied=12
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B
Fraction of total voids occupied=16
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C
Fraction of octahedral voids occupied=13
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D
Fraction of total voids occupied=19
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Solution
The correct option is DFraction of total voids occupied=19 According to the formula CrCl3 if there are 3Cl− ions , then there is 1Cr3+ ion. Cl− ions have a ccp arrangement.
So total number of octahedral voids are equal to the number of ions in ccp i.e. 3
Number of tetrahedral voids are twice the no of ions in ccp i.e. 6
1Cr3+ will occupy one octahedral void.
Total number of octahedral voids are 3 Fraction of octahedral voids occupied=13 Total number of voids=Tetrahedral voids +Octahedral voids=6+3=9 Fraction of total voids occupied=19
Option (c) and (d) are correct