wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In chromium (III) chloride, (CrCl3), chloride ions have cubic close packed arrangement and Cr (III) ions are present in octahedral voids.
Choose the correct option(s):

A
Fraction of octahedral voids occupied=12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Fraction of total voids occupied=16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Fraction of octahedral voids occupied=13
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Fraction of total voids occupied=19
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Fraction of total voids occupied=19
According to the formula CrCl3 if there are 3 Cl ions , then there is 1 Cr3+ ion.
Cl ions have a ccp arrangement.

So total number of octahedral voids are equal to the number of ions in ccp i.e. 3
Number of tetrahedral voids are twice the no of ions in ccp i.e. 6

1 Cr3+ will occupy one octahedral void.
Total number of octahedral voids are 3
Fraction of octahedral voids occupied=13
Total number of voids=Tetrahedral voids +Octahedral voids=6+3=9
Fraction of total voids occupied=19
Option (c) and (d) are correct

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon