CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In circle of radius 5cm,AB and AC are the two chords such that AB=AC=6cm. Find the length of chord BC.

Open in App
Solution

AD is the bisector of BAC and perpendicular bisector of BC passing through centre O. ¯¯¯¯¯¯¯¯¯AD and ¯¯¯¯¯¯¯¯BC at midpoint M.
¯¯¯¯¯¯¯¯¯¯BM=¯¯¯¯¯¯¯¯¯¯CM
In right angled triangle, AMC
MC2=AC2AM2=36AM2
In right angled triangle, OMC
MC2=OC2OM2
=25(AOOM)2=25(5AM)2
36AM2=25(5AM)2
or AM=3.6cm
¯¯¯¯¯¯¯¯¯¯MC=36(3.6)2
=23.044.8cm
BC=2MC
BC=2×4.8=9.8cm
665751_627653_ans_a29989404f1041699f1abfda82b9abe5.png

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circles and Their Chords - Theorem 3
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon