Question

In circuit shown below if $\alpha =0.4$, switching frequency is 50 Hz, then peak-to-peak ripple voltage of the capacitor is _________ V.

• A. 290.91

Answer 1

The correct option is A 290.91
$V_0=\frac{\alpha }{1-\alpha }{V}_s=\frac{0.4}{0.6}\times 120$

$V_0=80V$

$I_0=\frac{V_0}{R}=\frac{80}{10}=8A$

$\Delta V=\frac{I_0\alpha }{fC}=\frac{8\times 0.4}{50\times 220\times {10}^{-6}}$

$\Delta V=290.91V$