Question

In classical physics the force F acting on a body is assumed to be the product of mass m and acceleration a.If m=2.31 kg and acceleration is $3.123m/s^2$,then taking into account significant figures the force F should be reported as

• A. 7.21413 N
• B. 7.2141 N
• C. 7.214 N
• D. 7.21 N

Answer 1

Answer: (D)

7.21 N

$F=m\times a$

$=2.31\times 3.123=7.21413N$

Rounding off two decimal places since one of the products has two decimal places only.

$F=7.21N$