Question

In $[Co{F}_6{]}^{-3},C{o}^{3+}$ uses outer d orbits (4d) in $s{p}^3{d}^2$ hybridization. The number of unpaired electrons present in complex ion is.

• A. 0
• B. 4
• C. 2
• D. 3

Answer 1

Answer: (B)

4

As the $C{o}^{3+}$ has a configuration as follows:
$\left[Ar\right]3d^{6}4s^0$ ,

Now, as the $F^{-}$ is the weak field ligand, so does not cause the paring of the $3d^6$ electrons, so it has 2 pair electrons and 4 unpaired electrons in 3d orbitals.

In $[Co{F}_6{]}^{3-},C{o}^{3+}$ uses outer d orbitals (4d) in $s{p}^3{d}^2$ hybridization. The number of unpaired electrons present in complex ion is 4.