In cold water, bleaching powder ionises to form :

C a^{2 +}, C l^{-}

and

O C l^{-}

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C a O, C l^{-}

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C a^{2 +}, C l^{-}

and

C l O_{3}^{-}

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C a^{2 +}, C l^{-}

and

C l O_{2}^{-}

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Solution

The correct option is A $C a^{2 +}, C l^{-}$ and $O C l^{-}$
$C a (O C l) C l \to C a^{+ 2} + C l^{-} + O C l^{-}$

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Similar questions

The correct order of ionic size of the species $K^{+}, C l^{-}, C a^{2 +}$ and $S^{2 -}$ is:

S^{2 -}, N a^{+}, C a^{2 +}, C l^{-}

K^{+}, C l^{-}, S^{2 -}, C a^{2 +}

S^{2 -}, K^{+}, C a^{2 +}, C l^{-}

Which of the following option shows the correct symbol and charge of elements present in $C a {C l}_{2}$ ?

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