In column I, a uniform bar of uniform cross-sectional area under the application of forces is shown in the figure and in Column II, some effects/phenomena are given. Match the entries of Column I with the entries of Column II.

I \to Q, S; I I \to P, R; I I I \to R, P; I V \to S, P

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I \to P, R; I I \to P, S; I I I \to Q, S; I V \to Q, R

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I \to R, Q; I I \to Q, S I I I \to R, P; I V \to P, S

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I \to S, P; I I \to R, S; I I I \to Q, S; I V \to S, P

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Solution

The correct option is B $I \to P, R; I I \to P, S; I I I \to Q, S; I V \to Q, R$
For A and B, the rod is in equilibrium and hence internal restoring force developed per unit area across any cross section is same and stress developed in the rod is uniform, while in C and D, the case is reverse.

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In column I, a uniform bar of uniform cross-sectional area under the application of forces is shown in the figure and in Column II, some effects/phenomena are given. Match the entries of Column I with the entries of Column II.

The correct option is B I→P,R;II→P,S;III→Q,S;IV→Q,RFor A and B, the rod is in equilibrium and hence internal restoring force developed per unit area across any cross section is same and stress developed in the rod is uniform, while in C and D, the case is reverse.

The correct option is B $I \to P, R; I I \to P, S; I I I \to Q, S; I V \to Q, R$
For A and B, the rod is in equilibrium and hence internal restoring force developed per unit area across any cross section is same and stress developed in the rod is uniform, while in C and D, the case is reverse.