Question

In common emitter amplifier, the $\frac{I_c}{I_e}$ is $0.98$.The current gain will be

• A. $4.9$
• B. $7.8$
• C. $49$
• D. $78$

Answer 1

Answer: (C)

$49$

Given : $T_c=0.98I_e$

Using $I_e=I_c+I_b$

$\therefore$ $I_e=0.98I_e+I_b$ $⟹I_b=0.02I_e$

Current gain, $\beta =\frac{I_c}{I_b}=\frac{0.98I_e}{0.02I_e}=49$