In compound HC triple bondC- CH2- CH= CH- CH3,the C2- C3 bond is the type of :(1) sp- sp2(3) sp - sp3(2) sp3 -sp3(4) sp2 sp2

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Q. In the compound

C H_{3} - C H = C H - C H_{2} - C \equiv C H

, the hybridisation of C₁, C₃ and C₅ bonds respectively is

Q. In the compound,

6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C H \equiv 1 C H_{2}

C_{2} - C_{3}

bond is of :

In the organic compound $C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H$ , the pair of hydridised orbitals involved in the formation of: $C_{2} - C_{3}$ bond is:
(a) $s p - s p^{2}$ (b) $s p - s p^{3}$ (c) $s p^{2} - s p^{3}$ (d) $s p^{3} - s p^{3}$

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon are respectively:

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon sequentially are:

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