in compound interest,how do you find percentage increase in money deposited?

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Solution

$Let the principal be x . Amount = x {(1 + \frac{R}{100})}^{t} Percentage increase = \frac{x {(1 + \frac{R}{100})}^{t} - x}{x} \times 100 = ({(1 + \frac{R}{100})}^{t} - 1) \times 100 ANS . . .$

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in compound interest,how do you find percentage increase in money deposited?

Let the principal be x.Amount=x1+R100tPercentage increase=x1+R100t-xx×100=1+R100t-1×100 ANS...

$Let the principal be x . Amount = x {(1 + \frac{R}{100})}^{t} Percentage increase = \frac{x {(1 + \frac{R}{100})}^{t} - x}{x} \times 100 = ({(1 + \frac{R}{100})}^{t} - 1) \times 100 ANS . . .$