In concersion of lime-stone to lime- CaCO 3 s - CaO s - CO 2 g the values of - H 0 and - S 0 are -179-1 kJ mol -1 and 160-2 J - K respectively at 298 K and 1 bar-Assuming that - H 0 and - S 0 do not change with temperature- temperature above which conversion of limestone to lime will be spontaneous isA- 1118 KB- 1008 KC- 1200 KD- 845 K

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Byju's Answer

Standard XII

Chemistry

Second Law of Thermodynamics

In concersion...

Question

In concersion of lime-stone to lime,

$C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$ the values of $Δ H^{0}$ and $Δ S^{0}$ are $+ 179.1 k J m o l^{- 1}$ and $160.2 J / K$ respectively at 298 K and 1 bar. Assuming that $Δ H^{0}$ and $Δ S^{0}$ do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is

1118 K

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1008 K

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1200 K

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845 K

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Solution

The correct option is A
1118 K

$Δ G^{0} = Δ H^{0} - T Δ Δ^{0}$
For a spontaneous reaction $Δ G^{0} < 0$

or $Δ H^{0} - T Δ^{0} < 0 \Rightarrow T > \frac{Δ H^{0}}{Δ S^{0}}$

$\Rightarrow T > \frac{179.3 \times 10^{3}}{160.2} > 1117.9 K \approx 1118 K$

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