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Standard XII

Physics

Braking Radiation

In cooling tu...

Question

In cooling tube, the potential difference between cathode and anticathode is 120 kV. The maximum energy of emitted X-rays will be :-

1.2 \times 10^{5}

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10^{10}

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10^{15}

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10^{20}

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Solution

The correct option is A $1.2 \times 10^{5}$ eV
Given,
$V_{0} = 120 k V$
The maximum energy of emitted X-ray will be,
$K_{m a x} = e V_{0}$
$K_{m a x} = 120 e V = 1.2 \times 10^{5} e V$
The correct option is A.

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In cooling tube, the potential difference between cathode and anticathode is 120 kV. The maximum energy of emitted X-rays will be :-

The correct option is A 1.2×105 eVGiven,V0=120kVThe maximum energy of emitted X-ray will be,Kmax=eV0 Kmax=120eV=1.2×105eVThe correct option is A.

The correct option is A $1.2 \times 10^{5}$ eV
Given,
$V_{0} = 120 k V$
The maximum energy of emitted X-ray will be,
$K_{m a x} = e V_{0}$
$K_{m a x} = 120 e V = 1.2 \times 10^{5} e V$
The correct option is A.