In $C u S O_{4} .5 H_{2} O$ all Cu-O bond length are not equal. Find the total number of shorter Cu-O bonds.

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Solution

In $C u S O_{4} .5 H_{2} O$ structure is distorted octahedral.
There are four bonds between $C u$ and oxygen which is $1.958 o A$ .
Two bonds between oxygen atom of $S O_{4}^{- 2}$ and $C u$ , which is $2.385 o A$ .
Therefore, total number of shorter $C u - O$ bonds will be four.

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