In cycloalkanes the hybridisation of $C$ atoms is:

s p

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{s p}^{2}

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{s p}^{3}

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{s p}^{2} d

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Solution

The correct option is D ${s p}^{3}$
Cycloalkanes have $C - C$ single bonds. So, the hybridisation is $s p^{3}$

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Similar questions

N O_{3}^{-}, N O_{2}^{+}, N H_{4}^{+}

In the molecule CH ≡ C -CH = $C H_{2}$ , the hybridisation of C -Cbond is

H_{3} B O_{3}

N \equiv C^{1} - C^{2} H = C H_{2}

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

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