In ΔABC, AB = AC and the bisector of ∠B and ∠C meet at a point O, then ΔOBC is
Isosceles Triangle
∠B = ∠C (angles opposite to equal sides of a triangle)
∠OBC = ∠OCB (OB and OC are bisectors)
Then OB = OC (sides opposite to equal angles of a triangle)
Hence, ΔOBC is an isosceles triangle.