In ΔABC, BC = AB and ∠B = 80°, then ∠A is equal to:
100o
40o
80o
50o
In ΔABC, BC = AB and ∠B=80∘. Then, ∠A=?(a) 50∘ (b) 40∘ (c) 100∘ (d) 80∘
In ΔABC, AB = AC and ∠B=50∘. Then ∠A=?(a) 40∘ (b) 50∘ (c) 80∘ (d) 130∘
In a ΔABC, if AB=AC and BC is produced
to D such that ∠ACD=100∘, then ∠A=