In ΔABC, if ∠A = 100°, AD bisects ∠A and AD ⊥ BC. Then, ∠B =

(a) 50°

(b) 90°

(c) 40°

(d) 100°

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Solution

In the given ΔABC,, AD bisects and .

Here, we need to find.

As, AD bisects,

We get,

Now, according to angle sum property of the triangle

In ΔABD

Hence,

Therefore, the correct option is (c).

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∠ A

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Question 40

In $Δ A B C$ , $∠ A = 100^{\circ}$ , AD bisects $∠ A$ and $A D ⊥ B C$ . Then, $∠ B$ is equal to

a) $80^{\circ}$
b) $20^{\circ}$
c) $40^{\circ}$
d) $30^{\circ}$

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