Question

In $\Delta ABC,\angle A={72}^{\circ }$ and $\angle B={68}^{\circ }.$ Find $\angle C$

Answer 1

Given

In $△ABC,$

$\angle A={72}^{\circ },\angle B={68}^{\circ }$

As we know that

$\angle A+\angle B+\angle C={180}^{\circ }$

${68}^{\circ }+{72}^{\circ }+\angle C={180}^{\circ }$

$⟹\angle C={180}^{\circ }-{140}^{\circ }={40}^{\circ }$