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Question

In ΔABC BE and CF are the two equal altitudes. Prove ΔABC is isoceles by R.H.S

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Solution

GivenAEB=CEB=90(1)Also,CFisaaltitude,So,AFC=BFC=90(2)Also,BE=CF(3)WehavetoprovethatΔABCisisoceles.InΔBCFandΔCBEBFC=CEB=90FC=EB(from3)BC=CB(common)ΔBCFΔCBEbyRHScongruenceruleFBC=ECBso,ABC=ACBAB=ACHence,ΔABCisanisoscelestriangle.
1234333_1217687_ans_c76660ca6d374a98a9baf09a5c51f1a9.PNG

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