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Question

In ΔABC, a(cos2B+cos2C)+cosA(ccosC+bcosB)=

A
a
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B
b
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C
c
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D
0
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Solution

The correct option is A a
a(cos2B+cos2C)+cosA(ccosC+bcosB)
=acos2B+bcosBcosA+acos2C+ccosCcosA
=cosB(acosB+bcosA)+cosC(acosC+ccosA) (Using Projection Formula)
=ccosB+bcosC
=a

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