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Question

In ΔABC, a perpendicular AD is brawn to BC. If BD= 8 cm, DC = 2 cm and AD= 4 cm, then ___.


A

Δ is isosceles

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B

Δ ABC is equilateral

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C

AB=2AC

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D

Δ ABC is right angled at A

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Solution

The correct option is C

AB=2AC



Using Pythagoras' theorem in ΔADC,AC2=AD2+DC2.AC2=42+22=20 AC=20cm (1)Similarly, in ΔADBAB2=AD2+BD2 =42+82=80. AB=80cm=220cm (2) =2×AC (Using (2))


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