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Perimeter

In ΔABC, AB...

Question

In $Δ$ ABC, AB $= 10$ , AC $= 7$ , BC $= 9$ then find the Perimeter of triangle.

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Solution

Sides of triangle is $10, 7,, 9$
The perimeter of triangle is given as sum of all sides
$10 + 7 + 9 = 28$

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