Question

In $\Delta ABC$, $AB=5$,$BC=4$ and $AC=3$, then area of triangle is $12$ cm

• A. True
• B. False

Answer 1

The correct option is B False

Sides of triangle are $5,4,3$ cm respectively.

$S=(5+4+3)/2=6$

Using Heron's formula, area$=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{6(6-5)(6-4)(6-3)}=\sqrt{6\left(1\right)\left(2\right)\left(3\right)}=\sqrt{36}=6c{m}^2$

Hence above statement is false.