In $Δ$ ABC, AB = 5 cm. BC = 8 cm and CA = 7 cm. If D and E are respectively the mid-points of AB and BC determine the length of DE.

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Solution

In $Δ A B C, A B = 5 c m, B C = 8 c m$ and $C A = 7 c m$ . $D$ and $E$ are respectively the mid-points of $A B$ and $B C$ ,

$∴ D E = \frac{1}{2} A C = \frac{1}{2} \times 7 c m = 3.5 c m$ [Using the mid-point theorem]

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In ΔABC, AB = 5 cm. BC = 8 cm and CA = 7 cm. If D and E are respectively the mid-points of AB and BC determine the length of DE.

In ΔABC,AB=5cm,BC=8cm and CA=7cm. D and E are respectively the mid-points of AB and BC,∴DE=12AC=12×7cm=3.5cm [Using the mid-point theorem]

In $Δ$ ABC, AB = 5 cm. BC = 8 cm and CA = 7 cm. If D and E are respectively the mid-points of AB and BC determine the length of DE.

In $Δ A B C, A B = 5 c m, B C = 8 c m$ and $C A = 7 c m$ . $D$ and $E$ are respectively the mid-points of $A B$ and $B C$ ,

$∴ D E = \frac{1}{2} A C = \frac{1}{2} \times 7 c m = 3.5 c m$ [Using the mid-point theorem]