Question

In $\Delta$ABC, AB$=6\sqrt{3}$cm, AC$=12$cm and BC$=6$cm. The angle B is

• A. ${120}^o$
• B. ${60}^o$
• C. ${90}^o$
• D. ${45}^o$

Answer 1

The correct option is C ${90}^o$

$A{B}^2+B{C}^2=(6\sqrt{3}{)}^2+6^2$
$A{C}^2=144$
so $\angle B={90}^o$