In -ABC- AB -6-3cm- AC -12cm and BC -6cm- The angle B is

The correct option is C 90^o AB^2+BC^2=(6√(3))^2+6^2 AC^2=144 so ∠ B=90^o ...

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Apollonius's Theorem

In ΔABC, AB...

Question

In $Δ$ ABC, AB $= 6 \sqrt{3}$ cm, AC $= 12$ cm and BC $= 6$ cm. The angle B is

120^{o}

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60^{o}

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90^{o}

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45^{o}

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Solution

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Similar questions

Δ A B C,

A B = 6 \sqrt{3}

A C = 12

B C = 6

△ A B C, A B = 6 \sqrt{3} c m, A C = 12 c m

B C = 6 c m

∠ B

△ A B C

A B = 6 \sqrt{3}

12

B C = 6

B

△ A B C

A B = 6 \sqrt{3} c m, A C = 12 c m

B C = 6 c m

∠ B

Δ

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