Question

In $\Delta ABC$, AB = AC and AD is perpendicular to BC. State the property by which $\Delta ADB\cong \Delta ADC$.

• A. SAS property
• B. SSS property
• C. RHS property
• D. ASA property

Answer 1

The correct option is C RHS property

In $△ADB$ and $△ADC$

$AB=AC$ (given)

$AD=AD$ (common side)

$\angle ADB=\angle ADC={90}^{\circ }$ (As$AD\perp BC)$

$\therefore △ADB\cong △ADC$ by $RHS$ property.