In ΔABC, AB=BC=6cm. If a circle is drawn with center at B and radius 2 cm which intersects AB and BC at E and D, then ΔABC∼ΔEBD.
True
False
In ΔABCandΔEBD, BEBA=BDBC=26=13 and ∠ABC=∠EBD. ∴ By SAS similarity, ΔABC and ΔEBD are similar.