In - ABC - AB - BC and AC - CD and - B - x 0 and - D - y 0 then x 0-4 y 0 equal -A- 180-B- 1100C- 3600D- 1850E- 210-

The correct option is A 1800 ∠ACB = 2y ∠ACB =∠BAC ⇒ x + 2y+ 2y = 180^0 ⇒ x + 4y = 180^0 ...

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In $Δ$ ABC, AB = BC and AC = CD and $∠$ B = x $^{0}$ and $∠$ D = y $^{0}$ then x $^{0}$ +4 y $^{0}$ equal -

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