In - ABC - AC -15 cm and DE BC- If AD - DB -1-2- then AE -A- 5 cmB- 10 cmC- 7-5 cmD- 12-5 cm

The correct option is A 5 cmFrom Basic Proportionality theorem, AD/DB=AE/EC ⇒AE/EC=1/2 AC=15cm ⇒ AE+EC=15cm ⇒ EC = 2 AE ⇒ 3AE=15 cm ⇒ AE=5 cm ...

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Basic Proportionality Theorem

In Δ ABC , AC...

Question

In $Δ$ ABC, AC = 15 cm and DE $∥$ BC. If $\frac{A D}{D B} = \frac{1}{2}$ , then AE=

5 cm

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10 cm

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7.5 cm

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12.5 cm

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Δ

\frac{A D}{D B} = \frac{1}{2}

Δ

∥

\frac{A B}{A D} = 3

In $Δ A B C, A C = 15 c m$ and $D E ∥ B C$ . If $\frac{A B}{A D} = 3$ , find EC.

I n t h e Δ A B C, D E | | B C a n d \frac{A D}{D B} = \frac{2}{5} .

A C = 5.6 c m

A E =

Δ

D E ∥ B C

\frac{A B}{A D} = 3

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