In - ABC- AD is drawn such that - ABDand - ACD are equal in area then- the AD is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Medians of a Triangle and the Drawing Method

In Δ ABC, A...

Question

In $Δ A B C$ , AD is drawn such that $Δ A B D$ and $Δ A C D$ are equal in area then, the AD is

any segment drawn from A to BC

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the bisector of

∠ B A G

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A median of

Δ A B C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C A median of $Δ A B C$
The median of triangle cuts the triangle into two halves. Hence, AD is the median of $Δ A B C$

Suggest Corrections

Similar questions

$In the given figure, Δ A B D is an isosceles triangle with A B = A D . A median is drawn from A to side B D at C . Which of the following option(s) is/are correct?$

Q. In

Δ A B C

, AD is median of

Δ A B C

and BE is median of

Δ A B D

If ar

(Δ A B E) =

c m^{2}

, then ar

(Δ A B C)

Q. The area of

Δ A B C

400 c m^{2}

. If AD is a median of

Δ A B C

, then the area of

Δ A B D

200 c m^{2}

If AD is median of ΔABC and P is a point on AC such that ar(ΔADP) : ar(ΔABD) = 2 : 3, then ar(ΔPDC) : ar(ΔABC) is ______ .

Q. In a triangle

A B C

medians

A D

and

C E

are drawn. If

A D = 5, ∠ D A C = \frac{π}{8}, ∠ A C E = \frac{π}{4}

then area of

Δ A B C

is:

Join BYJU'S Learning Program

In ΔABC, AD is drawn such that ΔABDand ΔACD are equal in area then, the AD is

The correct option is C A median of ΔABCThe median of triangle cuts the triangle into two halves. Hence, AD is the median of ΔABC

In $Δ A B C$ , AD is drawn such that $Δ A B D$ and $Δ A C D$ are equal in area then, the AD is

The correct option is C A median of $Δ A B C$
The median of triangle cuts the triangle into two halves. Hence, AD is the median of $Δ A B C$