Question 28
In ΔABC, AD is the bisector of ∠A meeting BC at D, CF⊥AB and E is the mid-point of AC. Then, median of the triangle is
a) AD
b) BE
c) FC
d) DE
As we know, median of a triangle bisects the opposite sides
Here, the median is BE as AE = EC
Median divides the side of a triangle into two equal halves.